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10-2.Transmission of Heat
normal
Six identical conducting rods are joined as shown in figure. Points $A$ and $D$ are maintained at temperatures $200\,^oC$ and $20\,^oC$, respectively. the temperature of junction $B$ will be......... $^oC$

A
$120$
B
$100$
C
$140$
D
$80$
Solution

Resistance of all identical rods are same.
$\mathrm{H}_{1}=\mathrm{H}_{2}=\mathrm{H}_{3}$
$\frac{\mathrm{KA}\left(200-\theta_{1}\right)}{\ell}=\frac{\mathrm{KA}\left(\theta_{1}-\theta_{2}\right)}{\ell}=\frac{\mathrm{KA}\left(\theta_{2}-20\right)}{\ell}$
$\theta_{1}=140^{\circ} \mathrm{C} \quad \theta_{2}=80^{\circ} \mathrm{C}$
Standard 11
Physics